The sum of 3 terms of G.P is 21/4 and their product is b common ratio is
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Answer:
let first three terms a/r ,a , ar
a/c to question,
sum of first three terms = 39/10
⇒a/r + a + ar = 39/10
⇒a[1/r + 1 + r] = 39/10 ........(1)
again, product of first three terms = 1
⇒a/r × a × ar = 1
⇒a³ = 1 = 1³
⇒a = 1 , putting in equation (1),
we get, 1[1/r + 1 + r] = 39/10
⇒(1 + r + r²)/r = 39/10
⇒10(1 + r + r²) = 39r
⇒10 + 10r + 10r² = 39r
⇒10r² - 29r + 10 = 0
⇒10r² - 25r - 4r + 10 = 0
⇒5r(2r - 5) - 2(2r - 5) = 0
⇒(5r - 2)(2r - 5) = 0
⇒r = 2/5 , 5/2
now, for a=1 and r = 2/5
three terms are ; 5/2, 1 , 2/5
now , a= 1 and r= 5/2
three terms are ; 2/5,1,5/2
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Answered by
4
Answer:
ok
Step-by-step explanation:
its r = 4
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