Question

The sum of ₹3000 is given in the form of 63 prizes,if the prize money is either ₹100 or ₹25.find the number of prizes of each type

Answer 1

Let the number of prizes of money 100 be x, and the number of prizes of cost 25 be y ;

x+y = 63

y = 63-x -------(1)

100x+25y = 3000

4x+y = 120

y = 120-4x ------(2)

63-x = 120-4x

4x-x = 120-63

3x = 57

x = 19

y = 63-x = 63-19

y = 44

Hence the number of prizes of cost 100 each are 19 while other type of prizes are 44

____________________

Answer 2

${ \underline{ \huge{ \bf {\pink{Required \: answer : }}}}}$

Given the sum of prizes money = 3000

➡ Total number of prizes = 63

➡ number of prizes cost = 100x

➡ number of prize of cost = 25

will be 63 - x

From the problem we can write

=> x × 100 (63 - x) 25 = 3000

=> 100x + 1575 - 25x = 3000

(transporting) 1575 on L.H.S to R.S.H

we get

=> 100x - 25x = 3000 - 1575

=> 75x = 1425

=> x = 1425÷ 75

=> x = 19

number of 100 prizes = 19

number of 25 prizes = 63 - 19

➡ answer = 44