Math, asked by tekaanal, 1 year ago

The sum of 333 consecutive even numbers is 787878.

Answers

Answered by amudharm1
0

Answer: 262624, 262626, 262628.

Step-by-step explanation:

Let the smallest no. be x, then,

x+(x+2)+(x+4)= 787878

3x+6=787878

3x= 787878-6

x= 787872÷3

X= 262624

Therefore the numbers are ;

X = 262624

X+2 = 262626

X+4 =262628

Answered by ferlywelch25
0

Answer:

The Answer is =46

Step-by-step explanation:

Call the first number in the sequence x.

The next even number in the sequence is x +2x, plus, 2

The sum of the 333 consecutive even numbers is:

x+ (x + 2)+ (x + 4) = 132x+(x+2)+(x+4)=132x, plus, left parenthesis, x, plus, 2, right parenthesis, plus, left parenthesis, x, plus, 4, right parenthesis, equals, 132

3x + 6= 1323 x, plus, 6, equals, 132

3x =1263, x, equals, 126

x = 42, equals, 42

Since x is the first number, x + 4x, plus, 4 is the third even number.

Thus, the third number in the sequence is 464646.

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