Question

The sum of (3a+2b+5c-3) , (4b-2c+9), (11a-3b-7c-8) and (-2a+b+c-6) is

(4a-6b+2)

(12a+4b-3c-8)

3a-5b-7c+9

12a-4b+3c+8

tell me plzz anwer now
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Answer 1

Answer:

12a + 4b - 3c - 8

Step-by-step explanation:

(3a + 3b + 5c -3) + (4b - 2c +9) + ( 11a - 3b - - 7c - 8) + (-2a + b + c - 6)

Therefore.....12a + 4b -3c - 8