Question

The sum of ( 3a²b) + (-2a²b) + (a²b)​

Answer 1

Answer:

3a²b-2a²b+a²b

a²b+a²b

= 2a²b

Answer 2

answer :

$(3 {a}^{2} b) + ( - 2 {a}^{2}b) + ( {a}^{2} b)$

$= 3 {a}^{2} b - 2 {a}^{2} b + {a}^{2} b$

$= 2 {a}^{2} b$

$hence \: your \: answer \: is \: 2 {a}^{2} b$