Question

the sum of 3conscutive even number is 66find the number​

Answer 1

$\huge\underline\mathrm{Question-}$

The sum of 3 conscutive even number is 66. Find the number.

$\huge\underline\mathrm{Answer-}$

$\large{\boxed{\rm{Numbers\:are\:20,22\:and\:24}}}$

$\huge\underline\mathrm{Explanation-}$

Let the consecutive numbers be n, n+2 and n+4

Now, according to the question,

n + n + 2 + n + 4 = 66

$\mapsto$ 3n + 6 = 66

$\mapsto$ 3n = 66 - 6

$\mapsto$ 3n = 60

$\mapsto$ n = $\cancel{\dfrac{60}{3}}$

$\large{\boxed{\rm{\red{n=20}}}}$

$\rule{200}1$

★ 1st consecutive number = n

$\mapsto$ 20

★ 2nd consecutive number = n + 2

$\mapsto$ 20 + 2

$\mapsto$ 22

★ 3rd consecutive number = n + 4

$\mapsto$ 20 + 4

$\mapsto$ 24

$\large{\boxed{\rm{\therefore\:Numbers\:are\:20,22\:and\:24}}}$

$\rule{200}2$

• V E R I F I C A T I O N :

Sum of three numbers = 66

$\mapsto$ n + n + 2 + n + 4 = 66

$\mapsto$ 20 + 22 + 24 = 66

$\mapsto$ 66 = 66

Hence verified!

Answer 2

$\huge\underline\mathfrak\red{Question:}$

Sum of three consecutive even numbers is 66. Find the numbers.

$\huge{\underline{\bf{\green{Answer:}}}}$

Let the first number be = x

Let the second number be = x + 2

Let the third number be = x + 2 + 2 = x + 4

Their sum = 66

According to the question :-

$\bf{x + x + 2 + x + 4 = 66}$

$\bf{3x + 6 = 66}$

$\bf{3x = 66 - 6}$

$\bf{3x = 60}$

$\bf{x = \frac{\cancel{60}}{\cancel{3} } }$

$\bf{x = 20}$

The numbers =

The first number = x = 20

The second number = x + 2 = 20 + 2 = 22

The third number = x + 4 = 20+4 = 24

$\bf{Hence, \: the \: numbers \: are}$

$\bf{\: =20,22,24}$