The sum of 3consecutive multiples of 12 is 324.what are the multiples
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Answered by
2
Let number are 12x, 12(x + 1) and 12(x + 2)
According to the question :
12x + 12(x + 1) + 12(x + 2) = 324
12(x + x + 1 + x + 2) = 324
3x + 3 = 27
3x = 24
x = 8
Hence, multiples are
12x = 12(8) = 96
12(x + 1) = 12(9) = 108
12(x + 2) = 12(10) = 120
According to the question :
12x + 12(x + 1) + 12(x + 2) = 324
12(x + x + 1 + x + 2) = 324
3x + 3 = 27
3x = 24
x = 8
Hence, multiples are
12x = 12(8) = 96
12(x + 1) = 12(9) = 108
12(x + 2) = 12(10) = 120
Answered by
3
Hey
Here is your answer,
Let the three consecutive multiples of 12 be x , x+12 , x + 24
Given that,
The sum of 3 consecutive multiples of 12 is 324
X + x + 12 + x + 24 = 324
3x + 12 = 324 - 24
3x + 12 = 300
3x = 300 - 12
3x = 288
X = 288/3
X = 96
Therefore ,
X = 96
X + 12 = 96 + 12 = 108
X + 24 = 96 + 24 = 120
So, the three consecutive numbers are 96 , 108 and 120.
Hope it helps you!
Here is your answer,
Let the three consecutive multiples of 12 be x , x+12 , x + 24
Given that,
The sum of 3 consecutive multiples of 12 is 324
X + x + 12 + x + 24 = 324
3x + 12 = 324 - 24
3x + 12 = 300
3x = 300 - 12
3x = 288
X = 288/3
X = 96
Therefore ,
X = 96
X + 12 = 96 + 12 = 108
X + 24 = 96 + 24 = 120
So, the three consecutive numbers are 96 , 108 and 120.
Hope it helps you!
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