Question

the sum of 3numbers in A. p the product of 1st and last is 56 find the numbers​

Answer 1

Step-by-step explanation:

Let the numbers are in AP be a - d, a, a + d

The sum of the three numbers in A.P. is 27,

a - d + a + a + d = 27

3a = 27

a = 9

The product of the first and last is 56,

(a - d)(a + d) = 56

a2 - d2 = 56

92 - d2 = 56

d2 = 81 - 56 = 25

d = ± 5

Then the numbers are 4, 9, 14.

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