Question

the sum of 3rd and 5th term of an ap is 30 and the sum of 4th and 8th term is 46 ​

Answer 1

Answer:

From the question,

a₃ + a₅ = 30

(a + 2d) + (a + 4d) = 30

a + 2d + a + 4d = 30

2a + 6d = 30    → (1)

a₄ + a₈ = 46

(a + 3d) + (a + 7d) = 46

a + 3d + a + 7d = 46

2a + 10d = 46    → (2)

Subtracting (1) from (2)

4d = 16

d = 16/4

d = 4

Therefore, Common difference = 4

Hope this helps! Thank you!