Question

The sum of 3rd and 7th term of an AP is 6 and their product is 8.find the sum of first 20 terms of the AP.

Answer 1

Here is your solution

Given:-

The sum of 3rd term and 7th term
=>a+2d+a+6d = 6
=>2a+8d = 6
After common taking
a + 4d = 3
a=3-4d ..................….......(1)

Their product is

(a+2d)×(a+6d) = 8 .........…(2)

Putting value of a = 3–4d in equation (2) to get

=>(a+2d)×(a+6d) = 8

=>(3–4d+2d)×(3–4d+6d) =8

=>(3–2d)×(3+2d) = 8

=>9–4d^2 = 8

=>4d^2 = 9-8

=>4d^2 = 1

=>d^2 = 1/4

=>d = 1/2.

From (1) a = 3–4d
a=> 3–4×1/2
a=>3-2
a=> 1

The sum of the first 16 terms

Sum of 16 terms = (20/2)[2a+(20-1)d]

= (20/2)[2×1 + (20–1)×1/2]

= 10[2+19/2]

= 10×23/2

= 230/2
=115

Hence,
The sum of first 20 term is 115

Hope it helps you

Answer 2

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