The sum of 4 consecutive even number is 107 more than the sum of three consecutive odd numberso. If the sum of smallest odd number and smallest even number is 55, what is the smallest even number?
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0
Solution
Let the four consecutive even numbers are =
x
,
(
x
+
2
)
,
(
x
+
4
)
,
(
x
+
6
)
and three consecutive odd numbers =
y
,
(
y
+
2
)
,
(
y
+
4
)
Acc to ques,
=>
x
+
y
=
55
------------Eqn(1)
and
[
(
x
)
+
(
x
+
2
)
+
(
x
+
4
)
+
(
x
+
6
)
]
−
[
(
y
)
+
(
y
+
2
)
+
(
y
+
4
)
]
=
107
=>
(
4
x
+
12
)
−
(
3
y
+
6
)
=
107
=>
4
x
−
3
y
=
107
−
6
=
101
-----------Eqn(2)
Multiplying eqn(1) by 3 and add it to eqn(2), we get :
=>
3
x
+
4
x
=
55
×
3
+
101
=>
7
x
=
165
+
101
=
266
=>
x
=
266
7
=
38
Answered by
1
I have tried my level best to simplify it
Hope it'll help you guyss!!
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