Question

the sum of 4 consecutive integers is 198

Answer 1

Let x, x+1,x+2, x +3 are the numbers

so

x + x +1 + x +2 +x +3 = 198

4x + 6 = 198

4x =198-6

4x = 192

 x = 192/4

 x = 48

 x + 1 = 48 + 1 = 49

 x + 2 = 48 + 2 = 50

 x + 3 = 48 + 3 = 51

proof

48 + 49 + 50 + 51 = 198

so the numbers are 48, 49, 50, 51

fourth number in this sequence is 51

Answer 2

Answer:

51

Step-by-step explanation: