Question

The sum of 4
Consecutive integers is
198
What is the fourth
number in this
sequence?​

Answer 1

Call the first number in the sequence x.

The next integer in the sequence is x, plus, 1

The sum of the 4 consecutive integers is: x, plus, left parenthesis, x, plus, 1, right parenthesis, plus, left parenthesis, x, plus, 2, right parenthesis, plus, left parenthesis, x, plus, 3, right parenthesis, equals, 198

4, x, plus, 6, equals, 198

4, x, equals, 192

x, equals, 48

Since x is the first number, x, plus, 3 is the fourth integer.

Thus, the fourth number in the sequence is 51.

Answer 2

Call the first number in the sequence x.

The next integer in the sequence is x, plus, 1

The sum of the 4 consecutive integers is: x, plus, left parenthesis, x, plus, 1, right parenthesis, plus, left parenthesis, x, plus, 2, right parenthesis, plus, left parenthesis, x, plus, 3, right parenthesis, equals, 198

4, x, plus, 6, equals, 198

4, x, equals, 192

x, equals, 48

Since x is the first number, x, plus, 3 is the fourth integer.

Thus, the fourth number in the sequence is 51.