Question

The sum of 4 consecutive integers is 2010.Find the integers.​

Answer 1

Step-by-step explanation:

lets x first

x+1 second

X+2 third

x+3 Forth

then

2010=x+x+1 +x+2+x+3

4x+6=2010

4x=2010-6

4x=2004

x=2004/4

x=501

numbers are

501, 502 ,503, and 504

Answer 2

Answer:

501,502,503,504

Step-by-step explanation:

let integers be x,x+1,x+2,x+3

then, according to the question,

x+x+1+x+2+x+3=2010

4x+6=2010

4x=2004

x=2004÷4

x=501.

Therefore, the integers are-

a)x=501

b)x+1=502

c)x+2=503

d)x+3=504.

Hope it helps!