Question

The sum of
4

consecutive integers is 326
.
What is the second number in this sequence?

Answer 1

Answer:

Let the required numbers be x, (x+1), (x+2) and (x+3).

Atq,

x+(x+1)+(x+2)+(x+3) = 326

=> x+x+1+x+2+x+3 = 326

=> 4x+6 = 326

=> 4x = 326-6

=> 4x = 320

$= > x = \frac{320}{4} \\ = > x = 80$

Hence, the second number in this sequence is (80+1) = 81

Answer 2

Let the numbers be x,x+1,x+2,x+3

ATQ

x,x+1,x+2,x+3=326

4x+6=326

4x=320

X=80

So the numbers are 80 ,81 ,82 and 83

Now mark it BRAINLIEST please and sorry for that