the sum of 4 consecutive integers is 326. What is the second number in this sequence
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let the smallest number be x
then the four would be x,x+1,x+2,x+3
x+x+1+x+2+x+3=326
4x+6=326
4x=320
x=80
so they are x= 80
x+1=81
x+2=82
x+3=83
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