The sum of 4 consecutive integers is 406. Find the integers
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Let the four consecutive integers be
n, n+1, n+2, n+3
n + n + 1 + n + 2 + n + 3 = 406
4n + 6 = 406
4n = 400
n = 100
The required integers are = 100, 101, 102, 103
Hope it may help you !!!!!
n, n+1, n+2, n+3
n + n + 1 + n + 2 + n + 3 = 406
4n + 6 = 406
4n = 400
n = 100
The required integers are = 100, 101, 102, 103
Hope it may help you !!!!!
Answered by
0
Answer:
Step-by-step explanation:
101102103104
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