the sum of 4 consecutive integers is 70 then the greatest among them is
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Let 4 consecutive integers are
x,x+1,x+2,x+3
a/q
x+x+1+x+2+x+3=70
4x+6=70
4x=70-6
4x=64
x=64/4=16
hence, greatest integer is 16+3=19
x,x+1,x+2,x+3
a/q
x+x+1+x+2+x+3=70
4x+6=70
4x=70-6
4x=64
x=64/4=16
hence, greatest integer is 16+3=19
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