Question

the sum of 4 consecutive integers is130.
what is the third number in this sequence. ​

Answer 1

Answer:

33

Step-by-step explanation:

let 4 consecutive nos. are => x,x+1,x+2,x+3

now => (x)+(x+1)+(x+2)+(x+3) = 130

=> 4x +6 = 130

=> 4x = 124

X = 31

if x is 31 then

third no is 33

Answer 2

Answer:

33

Step-by-step explanation:

let the numbers be :-

(x) , (x+1) , (x+2) & (x+3)

now according to the question,

the sum of 4 consecutive numbers is 130

=> ( x ) + ( x+1 ) + ( x+2 ) + ( x+3 ) = 130

=> 4x + 6 = 130

=> 4x = 130 - 6

=> 4x = 124

=> x = 124/4

=> x = 31

Now, since we are asked to find out the third number in sequence so , the required number would be

( x+3 ) = 31+3 = 4

HOPE IT HELPS YOU