Question

The sum of 4 consecutive natural numbers each divisible by 5 is 130. What is the greatest number

Answer 1

Answer:

40

Step-by-step explanation:

Let the nos be 5x, 5(x+1), 5(x+2) and 5(x+3),as all are divisible by 5 and are consecutive.

ATQ,

5x+5(x+1)+5(x+2)+5(x+3)= 130

5(x+x+1+x+2+x+3)=130

4x+6=26

2(2x+3)=26

2x+3=13

2x=10

x=5..

the nos are-

5x= 5*5=25

5(x+1)= 5*6=30

5(x+2)= 5*7=35

5(x+3)= 5*8=40

SO THE GREATEST NO, IS 40