Question

The sum of 4 consecutive number is 50.find the largest number?

Answer 1

Answer:

Step-by-step explanation:

the consecutive four digits in the form (a+d)(a+2d)(a-2d)(a-d)

now

= a + d + a + 2d + a - 2d + a -d = 50

= 4a = 50

= a = 25/2

Answer 2

Answer:

$\large{\boxed{\sf 14}}$

Step-by-step explanation:

Let the four consecutive numbers be x, (x + 1), (x + 2), and (x + 3) respectively.

According to the question;

x + x + 1 + x + 2 + x + 3 = 50

⇒ 4x + 6 = 50

⇒ 4x = 50 - 6

⇒ 4x = 44

⇒ x = 44/4

⇒ x = 11

Therefore, the consecutive numbers are:

• x = 11
• x + 1 = 12
• x + 2 = 13
• x + 3 = 14

Hence, the largest number is 14.