Question

The sum of 4 consecutive numbers is 130.
What is the third number in this sequence?

Answer 1

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let the numbers are ....

(x-1),X,(X+1),(X+2)

now according to the question...,

(x-1)+X+(X+1)+(X+2)=130

4x=130-2=128

X=32

the third number was=32+1=33

$\large\mathcal\red{hope\: this \: helps \:you......}$

Answer 2

Answer:

→ The third number is 33.

Step-by-step explanation:

→ let the numbers be

x-1

X

X+1

X+2

According to the given question:

→ (x-1)+X+(X+1)+(X+2)=130

→4x+2=130

→4x=128

→X=32

The third number is =32+1=33

Answer 3

Answer:

→ The third number is 33.

Step-by-step explanation:

→ let the numbers are

x-1

X

X+1

X+2

According to the given question:

→ (x-1)+X+(X+1)+(X+2)=130

→4x+2=130

→4x=128

→X=32

The third number is =32+1=33