The sum of 4 consecutive odd integers is 336, how do you find the largest integer?
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Answer:-
87
Solution:-
Let the smallest odd integer be x.
Then, the next three odd integers are:
(x+2),(x+4) and (x+6).
According to the question,
x+(x+2)+(x+4)+ (x+6)=336
4x+12=336
4x=336-12=324
x=324/4=81.
Thus the nos. are:
x=81
x+2=83
x+4=85
x+6=87.
So, the greatest among all is 87.
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87 is the correct answer
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