the sum of 4 consecutive odd number is 56. find the greatest of four numbers
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Answered by
7
let the four consecutive odd numbers be
X , X +2 ,X +4 , X + 6 ,
given:
their sum is 56.
by the given condition,
X + X +2+X +4 X + 6 = 56
X + X + X + X +2+4+6=56
4x +12= 56
4x = 56 -12
4x = 44
X = 44/4
X = 11
the value of greatest number=
X+6
= 11+6
= 17
Answered by
1
Answer:
let 2n+1,2n+3,2n+5,2n+7 are the 4 consecutive odd numbers
2n+1+2n+3+2n+5+2n+7=56
8n+16=56
8n=56-16
8n=40
n=40/8
n=5
odd numbers are 2(5)+1,2(5)+3,2(5)+5,2(5)+7
11,13,15,17
therefore the greatest of four numbers is 17.
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