Question

the sum of 4 consecutive odd numbers in 56, find the greatest of the 4 numbers?

Answer 1

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Answer:

The four consecutive odd integers adding to 56 are: 11, 13, 15 and 17

Explanation:

First, let's define the four consecutive odd integers. We will call the first odd integer i.

Then by definition of "odd consecutive" the next three will be:

i+2, i+4 and i+6

Knowing they add up to 56 we can write and then solve for i:

i+i+2+i+4+i+6=56

i+i+i+i+2+4+6=56

4i+12=56

4i+12−12=56−12

4i+0=44

4i=44

4i4=444

4i4=11

i=11

Then the other 3 consecutive odd integers will be:

i+2=13

i+4=15

i+6=17

Answer 2

Let first number be x

Then second odd number = x + 2

Third odd number = x + 4

Fourth odd number = x + 6

Adding them all

x + (x +2) + (x +4) + (x + 6) = 56

4x + 12 = 56

4x = 44

x = 11

Greatest odd number is x + 6.

So, answer is 11 + 6 = 17

Thank you.