Question

The sum of 4 consecutive odd numbers is 192. Find the smallest of these numbers​

Answer 1

Answer:

SOLUTION: what are four consecutive odd integers who's sum is 192. Let 'n' be the smallest integer. Then n+(n+2)+(n+4)+(n+6)=192, so 4n+12=192. Therefore n=45.

Answer 2

Answer:

Consecutive is 192.

Step-by-step explanation:

Explain:

191 , 189 , 187 , 185 .