Question

the sum of 4 consecutive odd numbers is 86.find the greatest of the four numbers​

Answer 1

Allow the greatest of the four integers to be n. The remaining three will be n−3,n−2, and n−1. Their sum will be :

n−3+n−2+n−1+n=86

⟹4n−6=86

⟹4n=92

→4n4=924

⟶n=23

So the greatest is 23

Proof:20+21+22+23=86

Answer 2

Answer:

take any odd consecutive odd numbers x>10

let's take => 1,3,5,7 they are consecutive odd no.

=1+x,3+x,5+x,7+x

ACCORDING to question

1+x+3+x+5+x+7+x=86

15+4x=86

x=71/4