Question

The sum of 4 consecutive terms of an AP is 32 and the sum of their squares is 276; find the terms.
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Answer 1

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Find four numbers in A.P. w...

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Asked on November 22, 2019 by

Satyam Tehreem

Find four numbers in A.P. whose sum is 32 and sum of squares is 276.

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ANSWER

Let the numbers be: a−3d,a−d,a+d,a+3d

a−3d+a−d+a+d+a+3d=32

4a=32

∴a=8

(a−3d)

+(a−d) +(a+d) +(a+3d) =276

4a +20d =276

20d =276−4(8) =20

∴d=1

Therefore the 4 numbers are: a−3d,a−d,a+d,a+3d=8−3,8−1,8+1,8+3={5,7,9,11}