The sum of 4 terms of an AP is 2 and product of extreme term is 2 find those numbers?
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let those 4 terms be a-2d,a-d,a,a+d,a+2d
their sum=4a=2 (given)
gives us a=1/2
product of extreme means multiplication of starting and end term!!
gives us (a-2d)x(a+2d)=2 .....(given)
where a=1/2
use (x+y)(x-y)=xsquare - ysquare
gives us
asquare -(2d)square =2
2d square = 1/4-2 =-7/4
since square of a no. can't be negative
that means
THERE IS ERROR IN YOUR QUESTION!! fix it
their sum=4a=2 (given)
gives us a=1/2
product of extreme means multiplication of starting and end term!!
gives us (a-2d)x(a+2d)=2 .....(given)
where a=1/2
use (x+y)(x-y)=xsquare - ysquare
gives us
asquare -(2d)square =2
2d square = 1/4-2 =-7/4
since square of a no. can't be negative
that means
THERE IS ERROR IN YOUR QUESTION!! fix it
PunithAB:
tan² a / tan² a = sin² a. prove this bro
yes so I have strucked. Mostly its error question
how can i prove that?? u r asking just random que.! based on nothing!
tan sqaure a/ tan sqaure a cancels out
gives us sin suare a = 1
No I asked only one question to prove
ur que. doesnt makes any sense! post the que. others will say the same!
no bro we have to prove tan square by tan square is equals to sin square a
sorry for that but ur que. ia illogical according to me
no bro this question is from 10 th board of Karnataka
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