Question

the sum of 4 terms of AP is 28 and product 2nd and 3 rd term is 48 find the terms​

Answer 1

Answer:

Step-by-step explanation:

Assuming the numbers to be a-3d, a-d, a+d, a+3d

With respect to the question:

a-3d+a-d+a+d+a+3d = 28

4a = 28

a = 28/4 = 7

(a-d)(a+d) = 48

a2 - d2 = 48

7^2 - d2 = 48

49 - d2 = 48

49-48 = d2

1 = d2

d = 1(+/-)

Terms of the AP =

a - 3d = 7 - 3(1) = 4

a-d = 7 - 1 = 6

a+d = 7+1 = 8

a+3d = 7 + 3(1) = 10

Therefore the terms of the AP are = 4,6,8,10

Verifying if the terms are correct:

1. 4 + 6 + 8 + 10 = 28 (Satisfies the first condition)

2. 6 * 8 = 48 (Satisfies the second condition)

Hope this helps you!!