The sum of 444 consecutive integers is 326
What is the second number in this sequence?
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Answer:
x=1st integer then x+1 x+2 and x+3 all add up to 326
x + x+1 + x+2 + x+3 = 326
4x +6 = 326
4x= 320
x = 80
the Second number is 81
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