Question

the sum of 45 terms of an A.P ​

Answer 1

Answer:

The sum of 45 terms of an A. P. is 3195.

Answer 2

Answer:

Let the first term be 'a'

Common difference be 'd'

s45 = 3195 \\   \frac{45}{2}  \times (2a + (45 - 1)d = 3195 \\  \frac{45}{2}  \times (2a + 44d) = 3195 \\ 45 \times (a + 22d) = 3195 \\ a + 22d = 71 \\ a + (23 - 1)d = 71 \\ t23 = 71

hope it helps