Question

The sum of 45terms of an ap is 3195 and find its 23rd term

Answer 1

Answer:

23 term is 71

Step-by-step explanation:

sum of an AP is 3195

formula:

Sum of n number = sn

first term = a

difference = d

no of total terms = n

sn=n/2{2a+(n-1)d}

solution:

sn=n/2{2a+(n-1)d}

n= 45 sn= 3195 d= 1 (since it is in AP)

3195 = 45/2 {2a + (45-1 ) *1}

3195/45=1/2(2a+44)

639/9=2/2(a+22)

71=a+22

a=49

now to find the 23rd term the formula is

Formula:

tn = a + (n-1) d

tn= nth term a= first term. d = difference

n= 23. a=49. d=1

t23=49+(23-1)*1

t23=49+22

=71

t23=71