Question

The sum of 4consecutive integers is 326.
What is the second number in this sequence?

Answer 1

let first number be x

second x+1

third x+2

fourth x+3

A.T.Q

x+x+1+x+2+x+3 = 326

4x+6=326

4x=326-6

4x=320

x=320/4

x=80

first number x=80

second x+1 =81

third x+2=82

fourth x+3=83

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