the sum of 4th and 8 th of an ap os 24 and the sum pf 6 th and 10 th terms is 44 find the first three terms of ap
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t4 + t8 = 24
=> a + (4-1)d + a + (8-1)d = 24
=> 2a + 10d = 24..........(i)
t6 + t10 = 44
=> 2a + 14d = 44.........(ii)
using elimination method,
SUBTRACTING (ii) and (i) ,
4d = 20
d = 5
Putting the value of d in equation (i) ,
2a + 10(5) = 24
=> 2a = -26
=> a = -13
first three terms are:-
-13 , -8 , -3 ,......
t4 + t8 = 24
=> a + (4-1)d + a + (8-1)d = 24
=> 2a + 10d = 24..........(i)
t6 + t10 = 44
=> 2a + 14d = 44.........(ii)
using elimination method,
SUBTRACTING (ii) and (i) ,
4d = 20
d = 5
Putting the value of d in equation (i) ,
2a + 10(5) = 24
=> 2a = -26
=> a = -13
first three terms are:-
-13 , -8 , -3 ,......
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