Question

The sum of 4th and 8th term of an ap is 24 and sum of 6th and 10th term is 44. Find the first 3 terms of ap.

Answer 1

HERE IS UR ANSWER FRIEND :----

Given: a4+a8=24

we know that an=a+(n-1)d

a+3d+a+7d=24

2a+10d= 24. (1)

similarly we have,

a6+a10 = 44

a+5d+a+9d = 44

2a+14d = 44. (2)

solving (1) and (2) by elimination method we have,

2a+10d-(2a+14d) = 24 - 44

2a+10d-2a-14d = -20

-4d=-20

d=5

put the value of d in equation (1)

2a+10(5) = 24

2a+50= 24

2a= 24-50

2a= -26

a=-13

The first three terms of the AP is given by:

a, a+d, a+2d

-13, -8, -3

HOPE U LIKE THE ANSWER.

Answer 2

Answer:

- 13 , - 8 , - 3 .

Step-by-step explanation:

Let the first term a and common difference be d.

We know :

t_n = a + ( n - 1 ) d

t_4 = a + 3 d

t_8 = a + 7 d

We have given :

t_4 + t_8 = 24

2 a + 10 d = 24

a + 5 d = 12

a = 12 - 5 d ....( i )

t_6 = a + 5 d

t_10 = a + 9 d

: t_6 + t_10 = 44

2 a + 14 d = 44

a + 7 d = 22

a = 22 - 7 d ... ( ii )

From ( i ) and  ( ii )

12 - 5 d = 22 - 7 d

7 d - 5 d = 22 - 12

2 d = 10

d = 5

We have :

a = 12 - 5 d

a = 12 - 25

a = - 13

Now required answer as :

- 13 , - 8 , - 3 .

Finally we get answer.