the sum of 4th and 8th term of an ap is 24 and the sum of its 6th and 10th term is 44 find the first three terms
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Answer:
a+3d+a+7d=24
2a+10d=24
a+2d=12................. 1
a+5d+a+9d=44
2a+14d=44
a+7d=22.................. 2
a=22-7d
substitute the above value in eqn 1
22-7d+2d=12
22+5d-12=5d+10=0
5d=-10
d=-2
a=36
ap=36, 34, 32
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