the sum of 4th and 8th term of an ap is 24 and the sum of 6th and 10th term is 34 find the first tearm and common difference
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Answer:Sum of the 4th and the 8th terms
= a+3d+a+7d = 2a+10d = 24, or
a + 5d = 12, or
a = 12–5d …(1)
Sum of the 6th and the 10th terms
a+5d+a+9d = 34, or
2a+14d = 34, or
a+7d = 17, or
a = 17–7d …(2)
Equate (1) and (2)
12–5d = 17–7d, or
7d-5d = 17–12, or
2d = 5, or
d = 2.5
So a = 17–7*2.5 = -0.5
Step-by-step explanation: hope it helps
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