the sum of 4th and 8th term of an AP is 38 and the sum of 7th and 12th term is 59 find the 41st term
Answers
Answered by
2
Answer:
4th term+8th term=38
a+(4-1)d+a+(8-1)d=38
2a+10d=38
a+5d=19
a=19-5d--------(1)
7th term +12th term=59
a+(7-1)d +a+(12-1)d=59
2a+6d+11d=59
2(19-5d)+17d=59 (using 1)
38-10d+17d=59
7d=59-38
7d=21
d=1/3
a=19-5(1/3)
=19-5/3
=(57-5)/3=52/3
Similar questions