The sum of 4th and 8th term of an AP is 54 and the sum of 7th and 12th terms is 89.find the first three terms of the AP.
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Answered by
10
Answer:
-3
Step-by-step explanation:
A4=a+3d
A8=a+7d
And
A6=a+5d
A10=a+9d
Then
a+3d+a+7d=24
a+5d+a+9d=44
By solving we get
(1)-- 2a+10d=24
(2)--2a+14d=44
By elimination we want to do that
We get d=5
Sub d value in (1) then
We get a=-13 then do
A1=a=-13
A2=a+d=-13+(5)=-8
A3=a+2d=-13+2(5)=-13+10=-3
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