Question

The sum of 4th and 8th term of arthametic progression is 24 and the sum of 6th and 10th term is 44 find the first three terms of arthametic progression

Answer 1

Step-by-step explanation:

a4 = a+3d

a8 = a+7d

a+3d+a+7d = 24

2a+10d =24

a+5d=12 (equation 1)

a6=a+5d

a10=a+9d

a+5d+a+9d=44

2a+14d=44

a+7d=22 (equation 2)

solving equation 1 & 2

we get

d = 5 and a = -13

therefore

a1 = a = -13

a2 = a+d = -13+5 = -8

a3 = a+2d = -13+10 = -3