Question

the sum of 4th and 8th term open ap is 24 and the sum of the 6th and 10th term is 44 . find the first three term of the AP.​

Answer 1

Answer:

4th term =a+3d

6th ". "=a+5d

sum=2a+8d=24--(1)

a+5d+a+9d=2a+14d=44--(2)

(2)-(1)

14d-8d=20

6d=20

d=20/6

=10/3--(3)

substitute (3) in (1)

2a+8×10/3=24

2a=72/3-80/3

2a= -8/3

a= -16/3

so the first 3 terms are

-16/3,-6/3,4/3

hope this helps if so then don't forget to thank and mark as brainliest...... :)

Answer 2

Answer:

refers to the attachment.