Question

The sum of 4th and 8th terms of
an A.P. is 24 and the sum of the
6th and 10th terms is 44. Find the
first three terms of the A.P.​

Answer 1

Answer:

Let 'a' be the 1st term and 'd' be the common difference of the A.P.

Now, t4=a+(n-1)d=a+3d.

and t8=a+(n-1)d=a+7d.

Therefore, A/Q

t4+t8=a+3d+a+7d=2a+10d--------------------------(1)

Again,

t6+t10=a+5d+a+9d=2a+14d-----------------------(2)

From (1)-(2) we get,

2a+10d-2a+14d=24d