Question

the sum of 4th and 8th terms of an AP is 24 and the sum of 6th and 10th terms is 44. find the first 3 terms of the AP.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

A4=a+3d

A8=a+7d

And

A6=a+5d

A10=a+9d

Then

a+3d+a+7d=24
a+5d+a+9d=44

By solving we get

(1)-- 2a+10d=24
(2)--2a+14d=44

By elimination we want to do that

We get d=5
Sub d value in (1) then
We get a=-13 then do

A1=a=-13
A2=a+d=-13+(5)=-8
A3=a+2d=-13+2(5)=-13+10=-3