Question

the sum of 4th and 8th terms of an AP is 24 and the term sum of 6th and 10th term is 44. the find the first three terms of AP.​

Answer 1

Step-by-step explanation:

The first three terms of the ap are -13,-8,-3

Answer 2

$\large{\underline{\bf{\pink{Answer:-}}}}$

✰ First three terms of AP are -13, 8 and -3

$\large{\underline{\bf{\blue{Explanation:-}}}}$

$\large{\underline{\bf{\green{Given:-}}}}$

✰ sum of 4th and 8th term = 24

✰ sum of 6th and 10th term = 44

$\large{\underline{\bf{\green{To\:Find:-}}}}$

✰ we need to find the first three terms of AP.

$\huge{\underline{\bf{\red{Solution:-}}}}$

Let a be the first term and d be the common difference of given AP.

then,

$T_4+T_8=24$

$:\implies \:(a+3d)+(a+6d)=24$

$:\implies \:2a+10d=24$

divide both side by 2.

$:\implies \:a+5d=12.............(1)$

$and \:T_6+T_10=44$

$:\implies \: (a+5d)+(a+9d)=44$

$:\implies \:2a+14d=44$

Divide both side by 2

$:\implies \:a+7d=22...........(2)$

By elimination method solving both equations.

we get,

• a = - 13
• d = 5

Now, First three terms of AP are as :-

-13, 8 and -3

━━━━━━━━━━━━━━━━━━━━━━━