Question

The sum of 4th n8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44
do the three sum of AP​

Answer 1

Answer:

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: </p><p>QuEsTiOn :- \: \star}}}}}$

The sum of 4th and 8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44. Find the first three sums of AP.

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

GIVEN:

Sum of 4th and 8th term of AP = 24

Sum of 6th and 10 terms fo AP = 44

TO FIND:

First three terms of AP

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

4th term: a + 3d and 8th term: a + 7d

==> a + 3d + a + 7d = 24

=> 2a + 10d = 24 ---(1)

6th term: a + 5d and 10th term = a + 9d

==> a + 5d + a + 9d = 44

==> 2a + 14d = 44 ----(2)

After solving both equation,

==> -4d = -20

==> d = 20/4

==> d = 5

Common Difference = 5

Substitute (d) in eq - (1)

$❥\: 2a \: + \: 10d \: = \: 24 \\ </p><p></p><p>❥ \: 2a \: + \: 10(5) \: = \: 24 \\ </p><p></p><p>❥ \: 2a \: + \: 50 \: = \: 24 \\ </p><p></p><p> ❥ \: 2a \: = \: 24 \: - \: 50 \\ </p><p></p><p>❥ \: a \: = \: -26/2 \\ </p><p></p><p>❥ \: a \: = \: -13 \\ </p><p>$

First term = -13

The first terms are:

First term = a = -13

Second term = a + d = -13 + 5 = -8

Third term = a + 2d = -13 + 10 = -3

$\mathfrak{\huge{\purple{\underline{\underline{Hence}}}}}$

❥ The first three terms are -13, -8 and -3.

Answer 2

Answer:

The sum of 4th n8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44

do the three sum of APThe sum of 4th n8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44

do the three sum of APThe sum of 4th n8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44

do the three sum of APThe sum of 4th n8th terms of an AP is 24 and the sum of the 6th and 10th terms is 44

do the three sum of AP