Question

The sum of 4th term and 8th term of an ap is 24 and sum of 6th term and 10th term is34. Find first term.

Answer 1

hope it helps thou.....

Answer 2

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$let \: a \: be \: the \: first \: term \: and \: d \: be \: the \: common \: difference \: of \: the \: ap \\ then \\ t _{4} + t _{8} = 24 \implies(a + 3d) + (a + 7d) = 24 \\ \implies2a + 10d = 24 \\ \implies \: a + 5d = 12 \: \: \: \: .......(1) \\ and \: t _{6} + t _{10} \implies(a + 5d) + (a + 9d) = 34 \\ \implies2a + 14d = 34 \\ \implies \: a + 7d = 17 ........(2)\\ on \: solving \: (1)and(2) \: we \: get \: a = -1/2 \: and \: d= 5/2$