Question

The sum of 4thand8th terms of an appointment is24and the sum of 6th and 10th is44.find the ap

Answer 1

Answer:

a4+a8=24

a6+a10=44

a+(4-1)d + a+(8-1)d =24

a+3d +a+7d=24

2a+10d=24————(1)

a+(6-1)d+ a+ (10-1)d=44

a+5d+a+9d=44

2a+14d=44————(2)

2a+ 10d= 24

2a+ 14d= 44

(-) (-) (-)

————————

-4d= -20

d=5

2a + 10 X 5 =24

2a + 50 =24

2a= -26

a= -13

AP= -13, -8, -3......