Question

the sum of 5/6, 7/18, 1/9​

Answer 1

Answer:

First of all ,what we should do is to take the L.C.M of those denominators

because that's the basic we've to do in an unlike fraction.

Here we've to take the L.C.M of 6,18,9

which is equal to 18 (3×3×2)

and now we've to make those fractions' denominator=18

$\frac{5}{6} \times \frac{3}{3} = \frac{15}{18}$

$\frac{7}{18} = \frac{7}{18}$

we don't have to do anything in 7/18 as it already has 18 as denominator,you can try multiplication with 1,but still result is same.

$\frac{1}{9} \times \frac{2}{2} = \frac{2}{18}$

and now

we've got

$\frac{15}{18} + \frac{7}{18} + \frac{2}{18} \\ = \frac{15 + 7 + 2}{18} \\ \frac{24}{18}$

so we've got 24/18 as the number,but we can further divide it by 3,as both 24 and 18 is divisible by 3

that is

$\frac{24 \div 3}{18 \div 3} = \frac{8}{6}$

but it's divisible by 2 now

$\frac{8 \div 2}{6 \div 2} = \frac{4}{3}$

therefore the correct answer for your question

is 4/3

hope it helps you