The sum of 5 consecitive multipples of 4 is 80 what is the smallest number
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Let 5 cons. multiples of 4
x, x+4, x+8, x+12, x+16
X+x+4+x+8+x+12+x+16=80
5x+40=80
5x=80-40
X=40/5
x=8
So multiples are
X=8
X+4=8+4=12
X+8=8+8=16
X+12=8+12=20
X+16=8+16=24
The smallest no will be 8
x, x+4, x+8, x+12, x+16
X+x+4+x+8+x+12+x+16=80
5x+40=80
5x=80-40
X=40/5
x=8
So multiples are
X=8
X+4=8+4=12
X+8=8+8=16
X+12=8+12=20
X+16=8+16=24
The smallest no will be 8
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